The only things in Rust that are real statements are `let` statements, and item statements (e.g. declaring an `fn` inside a function). All other statements are in fact expressions, although some always return `()` so they're not really useful as such.
Rust is susceptible to segfaults when overflowing the stack. Is Rust not memory safe then?
Of course, Go allows more than that, with data races it's possible to reach use after free or other kinds of memory unsafety, but just segfaults don't mark a language memory unsafe.
Go is most emphatically NOT memory-safe. It's trivially easy to corrupt memory in Go when using gorotuines. You don't even have to try hard.
This stems from the fact that Go uses fat pointers for interfaces, so they can't be atomically assigned. Built-in maps and slices are also not corruption-safe.
In contrast, Java does provide this guarantee. You can mutate structures across threads, and you will NOT get data corruption. It can result in null pointer exceptions, infinite loops, but not in corruption.
This is just wrong. Not that you can't blow up from a data race; you certainly can. Simply that any of these properties admit to exploitable vulnerabilities, which is the point of the term as it is used today. When you expand the definition the way you are here, you impair the utility of the term.
Serious systems built in memory-unsafe languages yield continual streams of exploitable vulnerabilities; that remains true even when those systems are maintained by the best-resourced security teams in the world. Functionally no Go projects have this property. The empirics are hard to get around.
There were CVEs caused by concurrent map access. Definitely denials of service, and I'm pretty sure it can be used for exploitation.
> Serious systems built in memory-unsafe languages yield continual streams of exploitable vulnerabilities
I'm not saying that Go is as unsafe as C. But it definitely is NOT completely safe. I've seen memory corruptions from improper data sync in my own code.
Go ahead and demonstrate it. Obviously, I'm saying this because nobody has managed to do this in a real Go program. You can contrive vulnerabilities in any language.
It's not like this is a small track record. There is a lot of Go code, a fair bit of it important, and memory corruption exploits in non-FFI Go code is... not a thing. Like at all.
Go is rarely used in contexts where an attacker can groom the heap before doing the attack. The closest one is probably a breakout from an exposed container on a host with a Docker runtime.
If you're certain, demonstrate it. It'll be the first time it's been demonstrated. Message board arguments like this are literally the only place this claim is taken seriously.
That's not an apple-to-apple comparison, since Rust is a low-level language, and also because `reqwest` builds on top of `tokio`, an async runtime, and `hyper`, which is also a HTTP server, not just a HTTP client. If you check `ureq`, a synchronous HTTP client, it only adds 43 packages. Still more, but much less.
And in Go I can build a production-ready HTTPS (not just HTTP) server with just the standard library and a few lines of code. (0 packages).
That Rust does not have standard implementations of commonly-used features (such as an async runtime) is problematic for supply chain security, since then everyone is pulling in dozens (or hundreds) of fragmented 3rd-party packages instead of working with a bulletproof standard library.
And this is exactly why Go is winning: because it's actually rather easy to write "pure Go" utilities (no dependencies outside the standard library), which statically compile to boot (avoiding shared libraries).
FWIW, there is an accepted proposal (https://github.com/rust-lang/libs-team/issues/394) to add random number generation to std, and adding traits like in `num-traits` is wanted, but blocked on inherent traits.
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